The integral ∫(secx+tanx)29sec2xdxequals (for some arbitrary constant K)˙ −(secx+tanx)2111{111−71(secx+tanx)2}+K (secx+tanx)1111{111−71(secx+tanx)2}+K −(secx+tanx)2111{111+71(secx+tanx)2}+K (secx+tanx)2111{111+71(secx+tanx)2}+K

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The integral {{{{}^{{2}}{x}}}}{{{({{{x}}}+{{{x}}})}^{{{{9}}{{2

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The integral $\int \frac{sec ^{2} x}{( sec x + tan x ) ^{\frac{9}{2}}} d x$ equals (for some arbitrary constant $K) ˙$ $- \frac{1}{( sec x + tan x ) ^{\frac{11}{2}}} {\frac{1}{11} - \frac{1}{7} (sec x + tan x)^{2}} + K$ $\frac{1}{( sec x + tan x ) ^{\frac{1}{11}}} {\frac{1}{11} - \frac{1}{7} (sec x + tan x)^{2}} + K$ $- \frac{1}{( sec x + tan x ) ^{\frac{11}{2}}} {\frac{1}{11} + \frac{1}{7} (sec x + tan x)^{2}} + K$ $\frac{1}{( sec x + tan x ) ^{\frac{11}{2}}} {\frac{1}{11} + \frac{1}{7} (sec x + tan x)^{2}} + K$

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The integral

\int \frac{sec ^{2} x}{( sec x + tan x ) ^{\frac{9}{2}}} d x

equals (for some arbitrary constant

K) ˙

- \frac{1}{( sec x + tan x ) ^{\frac{11}{2}}} {\frac{1}{11} - \frac{1}{7} (sec x + tan x)^{2}} + K

\frac{1}{( sec x + tan x ) ^{\frac{1}{11}}} {\frac{1}{11} - \frac{1}{7} (sec x + tan x)^{2}} + K

- \frac{1}{( sec x + tan x ) ^{\frac{11}{2}}} {\frac{1}{11} + \frac{1}{7} (sec x + tan x)^{2}} + K

\frac{1}{( sec x + tan x ) ^{\frac{11}{2}}} {\frac{1}{11} + \frac{1}{7} (sec x + tan x)^{2}} + K

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Question Text	The integral $\int \frac{sec ^{2} x}{( sec x + tan x ) ^{\frac{9}{2}}} d x$ equals (for some arbitrary constant $K) ˙$ $- \frac{1}{( sec x + tan x ) ^{\frac{11}{2}}} {\frac{1}{11} - \frac{1}{7} (sec x + tan x)^{2}} + K$ $\frac{1}{( sec x + tan x ) ^{\frac{1}{11}}} {\frac{1}{11} - \frac{1}{7} (sec x + tan x)^{2}} + K$ $- \frac{1}{( sec x + tan x ) ^{\frac{11}{2}}} {\frac{1}{11} + \frac{1}{7} (sec x + tan x)^{2}} + K$ $\frac{1}{( sec x + tan x ) ^{\frac{11}{2}}} {\frac{1}{11} + \frac{1}{7} (sec x + tan x)^{2}} + K$
Answer Type	Video solution: 1
Upvotes	150