The integral ∫0π1+4sin2(2x)−4sin(2x)dxequal

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The integral {_{{0}}^{}}{{{1}+{4}{{}^{{2}}{({{x}}{{2}})}}-{4}{

Question

The integral $\int_{0}^{π} 1 + 4 sin^{2} (\frac{x}{2}) - 4 sin (\frac{x}{2}) d x$ equal

π - 4

\frac{2 π}{3} - 4 - 4 ∣ ∣

(3)

43 - 4

43 - 4 - \frac{π}{3}

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Question Text	The integral $\int_{0}^{π} 1 + 4 sin^{2} (\frac{x}{2}) - 4 sin (\frac{x}{2}) d x$ equal
Answer Type	Video solution: 1
Upvotes	150