The expression $^{n} C_{0} + 4^{n} C_{1} + 4^{2}^{n} C_{2} + .......... + 4^{n}^{n} C_{n}$ , equals

2^{2 n}

2^{3 n}

5^{n}

None of these

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The expression

^{n} C_{0} + 4^{n} C_{1} + 4^{2}^{n} C_{2} + .......... + 4^{n}^{n} C_{n}

, equals

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Text solutionVerified

We know that

^{n} C_{0} + 4^{n} C_{1} + 4^{2}^{n} C_{2} + ....... + 4^{n}^{n} C_{n} (1 + x)^{n} =^{n} C_{0} +^{n} C_{1} x +^{n} C_{2} x^{2} + ..... +^{n} C_{n} P u tt in g x = 4 5^{n} =^{n} C_{0} + 4^{n} C_{1} + 4^{2}^{n} C_{2} + ....... + 4^{n}^{n} C_{n} He n ce, o pt i o n C i s t h e correc t an s w er .

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Question Text	The expression $^{n} C_{0} + 4^{n} C_{1} + 4^{2}^{n} C_{2} + .......... + 4^{n}^{n} C_{n}$ , equals
Answer Type	Text solution:1
Upvotes	150