The coefficient of the middle term in the expansion of (1+x)2n is equal to the sum of the coefficient of middle terms in the expansion of (1+x)2n−1
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Evaluate the following: (1+2x)5+(1−2x)5
Using binomial theorem evaluate each of the following: (101)4
Find the number of terms which are free from radical signs in the expansion of (y1/5+x1/10)55˙
Coefficient of x2m+1 in the expansion of (1+x)(1+x2)(1+x4)(1+x8)…(1+x2m)1(∣x∣<1) is
Find the 7th term in the expansion of (3x2−x31)10˙
The co-efficient of x in the expansion of (1−2x3+3x5)(1+x1)8 is:
Middle term in expansion of (1−3x+3x2−x3)2n is
The sum of last 3 digits of 3100 is