Tangents drawn from point of intersection A of circles $x^{2} + y^{2} = 4$ and $(x - 3)^{2} + (y - 3)^{2} = 4$ cut the line joining their centres at B and C then triangle BAC is

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Tangents drawn from point of intersection A of circles

x^{2} + y^{2} = 4

and

(x - 3)^{2} + (y - 3)^{2} = 4

cut the line joining their centres at B and C then triangle BAC is

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Question Text

Tangents drawn from point of intersection A of circles

x^{2} + y^{2} = 4

and

(x - 3)^{2} + (y - 3)^{2} = 4

cut the line joining their centres at B and C then triangle BAC is

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