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Tangent to the curve {y}={x}^{{2}}+{6} at a point {({1},{7})}

Question

Tangent to the curve $y = x^{2} + 6$ at a point $(1, 7)$ touches the circle $x^{2} + y^{2} + 16 x + 12 y + c = 0$ at a point $Q$ , then the coordinates of $Q$ are (A) $(- 6, - 11)$ (B) $(- 9, - 13)$ (C) $(- 10, - 15)$ (D) $(- 6, - 7)$

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James Discussed

Tangent to the curve

y = x^{2} + 6

at a point

(1, 7)

touches the circle

x^{2} + y^{2} + 16 x + 12 y + c = 0

at a point

Q

, then the coordinates of

Q

are (A)

(- 6, - 11)

(B)

(- 9, - 13)

(C)

(- 10, - 15)

(D)

(- 6, - 7)

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Question Text	Tangent to the curve $y = x^{2} + 6$ at a point $(1, 7)$ touches the circle $x^{2} + y^{2} + 16 x + 12 y + c = 0$ at a point $Q$ , then the coordinates of $Q$ are (A) $(- 6, - 11)$ (B) $(- 9, - 13)$ (C) $(- 10, - 15)$ (D) $(- 6, - 7)$
Answer Type	Video solution: 1
Upvotes	150