tan−1(71 )+tan−1(131 )=cos−1(29 )

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{ }^{ -1 }( { 1 }{ 7 } ) +{ }^{ -1 }( { 1 }{ 13 } ) = ^{

Question

$tan^{- 1} (\frac{1}{7}) + tan^{- 1} (\frac{1}{13}) = cos^{- 1} (\frac{9}{2})$

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Scarlett Discussed

tan^{- 1} (\frac{1}{7}) + tan^{- 1} (\frac{1}{13}) = cos^{- 1} (\frac{9}{2})

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Question Text

tan^{- 1} (\frac{1}{7}) + tan^{- 1} (\frac{1}{13}) = cos^{- 1} (\frac{9}{2})