Solve the following differential equation : (x2−1)dxdy+2x y=(x2−1)2
The general solution of the differential equation exdy+(yex+2x)dx=0is(A) xey+x2=C (B) xey+y2=C (C) yex+x2=C (D) yey+x2=C
Verify that the given functions (explicit or implicit) is a solution of the corresponding differential equation: y=xsinx : xyprime=y+xx2−y2(x=0andx>yorx<y)
At any point (x, y) of a curve, the slope of the tangent is twice the slope of the line segment joining the point of contact to the point (4,3). Find the equation of the curve given that it passes through (2,1).