Solve: tan−1(tan32π)

tan−1tan32π=tan−1tan(π−3π)=tan−1(−tan(3π))=tan−1(−3)=−3π

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Solve: { ^{ - 1}}( { {{2 }}{3}} )

Question

Solve: $tan^{- 1} (tan \frac{2 π}{3})$

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Solve:

tan^{- 1} (tan \frac{2 π}{3})

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tan^{- 1} tan \frac{2 π}{3}

= tan^{- 1} tan (π - \frac{π}{3})

= tan^{- 1} (- tan (\frac{π}{3}))

= tan^{- 1} (- 3)

= - \frac{π}{3}

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