Solve : $(sin θ + cos θ) (sec θ + cosec θ) = 2 + sec θ cosec θ$

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(sin θ + cos θ) (sec θ + cosec θ) = 2 + sec θ cosec θ

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Text solutionVerified

(s in θ + cos θ) (sec θ + cosec θ)

\Rightarrow (s in θ + cos θ) (\frac{1}{cos θ} + \frac{1}{s in θ})

\Rightarrow (s in θ + cos θ) (\frac{s in θ + cos θ}{cos θ s in θ})

\Rightarrow \frac{( s in θ + cos θ ) ^{2}}{cos θ s in θ}

\Rightarrow \frac{s i n ^{2} θ + co s ^{2} θ + 2 s in θ cos θ}{cos θ s in θ}

\Rightarrow \frac{1}{cos θ s in θ} + 2

\Rightarrow 2 + sec θ cosec θ

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Question Text	Solve : $(sin θ + cos θ) (sec θ + cosec θ) = 2 + sec θ cosec θ$
Answer Type	Text solution:1
Upvotes	151