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{ ( ^{ -1 }{ 3 } ) } =

Question

$sin (tan^{- 1} 3) =$

\frac{1}{3}

\frac{3 10}{10}

\frac{1}{2}

\frac{2}{3}

\frac{3}{10}

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Text solutionVerified

We need to find value of

sin (tan^{- 1} 3)

Let

tan^{- 1} 3 = θ

, we get

tan θ = 3

∴ sin (tan^{- 1} 3) = sin θ = \frac{tan θ}{1 + tan ^{2} θ} = \frac{3}{10} = \frac{3 10}{10}

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