sin−1(53)+cos−1(1312)=sin−1(6556)

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{ }^{ -1 } ( { 3 }{ 5 } )+{ }^{ -1 } ( { 12 }{ 13 } )={ }^{

Question

$sin^{- 1} (\frac{3}{5}) + cos^{- 1} (\frac{12}{13}) = sin^{- 1} (\frac{56}{65})$

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sin^{- 1} (\frac{3}{5}) + cos^{- 1} (\frac{12}{13}) = sin^{- 1} (\frac{56}{65})

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Question Text

sin^{- 1} (\frac{3}{5}) + cos^{- 1} (\frac{12}{13}) = sin^{- 1} (\frac{56}{65})