sin−1(21)+sin−1(62−1)+…+sin−1(n(n+1)n−n−1)+….∞=

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^{-1}({1}{{2}})+ ^{-1}({{2}-1}{{6}})++ ^{-1}({{n}-{n-1}}{{n(n

Question

$sin^{- 1} (\frac{1}{2}) + sin^{- 1} (\frac{2 - 1}{6}) + \dots + sin^{- 1} (\frac{n - n - 1}{n ( n + 1 )}) + \dots .\infty =$

π

\frac{π}{2}

\frac{π}{4}

\frac{3 π}{2}

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Henry Discussed

sin^{- 1} (\frac{1}{2}) + sin^{- 1} (\frac{2 - 1}{6}) + \dots + sin^{- 1} (\frac{n - n - 1}{n ( n + 1 )}) + \dots .\infty =

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Question Text

sin^{- 1} (\frac{1}{2}) + sin^{- 1} (\frac{2 - 1}{6}) + \dots + sin^{- 1} (\frac{n - n - 1}{n ( n + 1 )}) + \dots .\infty =