sin−153+tan−1 71=2π

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{ ^{ -1 } { 3 }{ 5 } + { ^{ -1 } } } { 1 }{ 7 } = { }{ 2

Question

$sin^{- 1} \frac{3}{5} + tan^{- 1} \frac{1}{7} = \frac{π}{2}$

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sin^{- 1} \frac{3}{5} + tan^{- 1} \frac{1}{7} = \frac{π}{2}

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Question Text

sin^{- 1} \frac{3}{5} + tan^{- 1} \frac{1}{7} = \frac{π}{2}