Prove that:tan60∘tan80∘tan20∘ =tan80∘−tan20∘−tan60∘

tan60∘=tan(80∘−60∘)tan60∘=1+tan80∘⋅tan20∘tan80∘−tan20∘tan60∘+tan80∘.tan60∘.⋅tan20∘⋅tan60∘=tan80∘−tan20∘tan80∘⋅tan20∘⋅tan60∘=tan80∘−tan20∘−tan60∘

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Prove that: 60^80^20^ = 80^ - 20^ - 60^

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Prove that:
$tan 6 0^{\circ} tan 8 0^{\circ} tan 2 0^{\circ} = tan 8 0^{\circ} - tan 2 0^{\circ} - tan 6 0^{\circ}$

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Prove that:

tan 6 0^{\circ} tan 8 0^{\circ} tan 2 0^{\circ} = tan 8 0^{\circ} - tan 2 0^{\circ} - tan 6 0^{\circ}

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tan 6 0^{\circ} = tan (8 0^{\circ} - 6 0^{\circ})

tan 6 0^{\circ} = \frac{tan 8 0 ^{\circ} - tan 2 0 ^{\circ}}{1 + tan 8 0 ^{\circ} \cdot tan 2 0 ^{\circ}}

tan 6 0^{\circ} + tan 8 0^{\circ} . tan 6 0^{\circ} . \cdot tan 2 0^{\circ} \cdot tan 6 0^{\circ} = tan 8 0^{\circ} - tan 2 0^{\circ}

tan 8 0^{\circ} \cdot tan 2 0^{\circ} \cdot tan 6 0^{\circ} = tan 8 0^{\circ} - tan 2 0^{\circ} - tan 6 0^{\circ}

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Question Text	Prove that: $tan 6 0^{\circ} tan 8 0^{\circ} tan 2 0^{\circ} = tan 8 0^{\circ} - tan 2 0^{\circ} - tan 6 0^{\circ}$
Answer Type	Text solution:1
Upvotes	150