Question
Number of real solutions of the equation is
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Text solutionVerified
Multiplying both sides with 2, we get
Let
Hence
Now
However,
always,
Since
Hence range of values of RHS is not equal to LHS.
Thus no real solutions.
Let
Hence
Now
However,
always,
Since
Hence range of values of RHS is not equal to LHS.
Thus no real solutions.
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In an A.P., of which a is the first term, if the sum of the first p terms is zero, show that the sum of the next q terms is .Stuck on the question or explanation?
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Question Text | Number of real solutions of the equation is |
Answer Type | Text solution:1 |
Upvotes | 150 |