(lim)x1(ex−e)sinπxnxn+1−(n+1)xn+1,wheren=100, is equal to : πe5050 (b) πe100 (c) −πe5050 (d) −πe4950

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{({lim})}_{{{x}{{1}}}}{{{n}{x}^{{{n}+{1}}}-{({n}+{1})}{x}^{{n}

Question

$(lim)_{x 1} \frac{n x ^{n + 1} - ( n + 1 ) x ^{n} + 1}{( e ^{x} - e ) sin π x}, w h e r e n = 100,$ is equal to : $\frac{5050}{π e}$ (b) $\frac{100}{π e}$ (c) $- \frac{5050}{π e}$ (d) $- \frac{4950}{π e}$

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Liam Discussed

(lim)_{x 1} \frac{n x ^{n + 1} - ( n + 1 ) x ^{n} + 1}{( e ^{x} - e ) sin π x}, w h e r e n = 100,

is equal to :

\frac{5050}{π e}

(b)

\frac{100}{π e}

(c)

- \frac{5050}{π e}

(d)

- \frac{4950}{π e}

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Question Text

(lim)_{x 1} \frac{n x ^{n + 1} - ( n + 1 ) x ^{n} + 1}{( e ^{x} - e ) sin π x}, w h e r e n = 100,

is equal to :

\frac{5050}{π e}

(b)

\frac{100}{π e}

(c)

- \frac{5050}{π e}

(d)

- \frac{4950}{π e}