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Let {Z}_{{0}} is the root of equation {x}^{{2}}+{x}+{1}={0} an

Question

Let $Z_{0}$ is the root of equation $x^{2} + x + 1 = 0$ and $Z = 3 + 6 i (Z_{0})^{81} - 3 i (Z_{0})^{93}$ Then arg $(Z)$ is equal to (a) $\frac{π}{4}$ (b) $\frac{π}{3}$ (c) $π$ (d) $\frac{π}{6}$

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Sofia Discussed

Let

Z_{0}

is the root of equation

x^{2} + x + 1 = 0

and

Z = 3 + 6 i (Z_{0})^{81} - 3 i (Z_{0})^{93}

Then arg

(Z)

is equal to (a)

\frac{π}{4}

(b)

\frac{π}{3}

(c)

π

(d)

\frac{π}{6}

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Question Text

Let

Z_{0}

is the root of equation

x^{2} + x + 1 = 0

and

Z = 3 + 6 i (Z_{0})^{81} - 3 i (Z_{0})^{93}

Then arg

(Z)

is equal to (a)

\frac{π}{4}

(b)

\frac{π}{3}

(c)

π

(d)

\frac{π}{6}

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