Let y(x) is the solution of differential equation dxdy+y=xlogx and 2y(2)=loge4−1. Then y(e) is equal to (A) 2e2 (B) 2e (C) 4e (D) 4e2

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Let $y (x)$ is the solution of differential equation $\frac{d y}{d x} + y = x lo g x$ and $2 y (2) = lo g_{e} 4 - 1$ . Then $y (e)$ is equal to (A) $\frac{e ^{2}}{2}$ (B) $\frac{e}{2}$ (C) $\frac{e}{4}$ (D) $\frac{e ^{2}}{4}$

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Liam Discussed

Let

y (x)

is the solution of differential equation

\frac{d y}{d x} + y = x lo g x

and

2 y (2) = lo g_{e} 4 - 1

. Then

y (e)

is equal to (A)

\frac{e ^{2}}{2}

(B)

\frac{e}{2}

(C)

\frac{e}{4}

(D)

\frac{e ^{2}}{4}

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Question Text

Let

y (x)

is the solution of differential equation

\frac{d y}{d x} + y = x lo g x

and

2 y (2) = lo g_{e} 4 - 1

. Then

y (e)

is equal to (A)

\frac{e ^{2}}{2}

(B)

\frac{e}{2}

(C)

\frac{e}{4}

(D)

\frac{e ^{2}}{4}

Let $y (x)$ is the solution of differential equation $\frac{d y}{d x} + y = x lo g x$ and $2 y (2) = lo g_{e} 4 - 1$ . Then $y (e)$ is equal to (A) $\frac{e ^{2}}{2}$ (B) $\frac{e}{2}$ (C) $\frac{e}{4}$ (D) $\frac{e ^{2}}{4}$

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Practice questions from similar books

Let y(x) is the solution of differential equation dxdy​+y=xlogx and 2y(2)=loge​4−1. Then y(e) is equal to (A) 2e2​ (B) 2e​ (C) 4e​ (D) 4e2​

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Practice questions from similar books

Let $y (x)$ is the solution of differential equation $\frac{d y}{d x} + y = x lo g x$ and $2 y (2) = lo g_{e} 4 - 1$ . Then $y (e)$ is equal to (A) $\frac{e ^{2}}{2}$ (B) $\frac{e}{2}$ (C) $\frac{e}{4}$ (D) $\frac{e ^{2}}{4}$