Let the line 3x−2=−5y−1=2z+2lie in the plane x+3yαz+β=0. Then (α,β) equals

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Let the line {{{x}-{2}}}{{3}}={{{y}-{1}}}{{-{5}}}={{{z}+{2}}}{

Question

Let the line $\frac{x - 2}{3} = \frac{y - 1}{- 5} = \frac{z + 2}{2}$ lie in the plane $x + 3 y α z + β = 0$ . Then $(α, β)$ equals

(6, - 17)

(- 6, 7)

(5, - 15)

(- 5, 5)

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Jack Discussed

Let the line

\frac{x - 2}{3} = \frac{y - 1}{- 5} = \frac{z + 2}{2}

lie in the plane

x + 3 y α z + β = 0

. Then

(α, β)

equals

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Question Text	Let the line $\frac{x - 2}{3} = \frac{y - 1}{- 5} = \frac{z + 2}{2}$ lie in the plane $x + 3 y α z + β = 0$ . Then $(α, β)$ equals
Answer Type	Video solution: 1
Upvotes	150