Let S be the area of the region enclosed by y=e−x2,y=0,x=0,andx=1. Then (a)S≥e1 (b) S≥1=e1(c)S≤41(1+e1) (d) S≤21+e1(1−21)

Name: Video solution 1: Let S be the area of the region enclosed by y=e−x2,y=0,x=0,andx=1. Then (a)S≥e1 (b) S≥1=e1(c)S≤41(1+e1) (d) S≤21+e1(1−21)
Uploaded: 2021-01-01T18:41:02.000Z
Duration: 2 min
Description: Video solution 1: Let S be the area of the region enclosed by y=e−x2,y=0,x=0,andx=1. Then (a)S≥e1 (b) S≥1=e1(c)S≤41(1+e1) (d) S≤21+e1(1−21)

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Let {S} be the area of the region enclosed by {y}={e}^{{-{x}^{

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Let $S$ be the area of the region enclosed by $y = e^{- x^{2}}, y = 0, x = 0, a n d x = 1 .$ Then (a) $S \geq \frac{1}{e}$ (b) $S \geq 1 = \frac{1}{e}$ (c) $S \leq \frac{1}{4} (1 + \frac{1}{e})$ (d) $S \leq \frac{1}{2} + \frac{1}{e} (1 - \frac{1}{2})$

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Let

S

be the area of the region enclosed by

y = e^{- x^{2}}, y = 0, x = 0, a n d x = 1 .

Then (a)

S \geq \frac{1}{e}

(b)

S \geq 1 = \frac{1}{e}

(c)

S \leq \frac{1}{4} (1 + \frac{1}{e})

(d)

S \leq \frac{1}{2} + \frac{1}{e} (1 - \frac{1}{2})

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Question Text	Let $S$ be the area of the region enclosed by $y = e^{- x^{2}}, y = 0, x = 0, a n d x = 1 .$ Then (a) $S \geq \frac{1}{e}$ (b) $S \geq 1 = \frac{1}{e}$ (c) $S \leq \frac{1}{4} (1 + \frac{1}{e})$ (d) $S \leq \frac{1}{2} + \frac{1}{e} (1 - \frac{1}{2})$
Answer Type	Video solution: 1
Upvotes	150

Let S be the area of the region enclosed by y=e−x2,y=0,x=0,andx=1. Then (a)S≥e1​ (b) S≥1=e1​(c)S≤41​(1+e​1​) (d) S≤2​1​+e​1​(1−2​1​)

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Let $S$ be the area of the region enclosed by $y = e^{- x^{2}}, y = 0, x = 0, a n d x = 1 .$ Then (a) $S \geq \frac{1}{e}$ (b) $S \geq 1 = \frac{1}{e}$ (c) $S \leq \frac{1}{4} (1 + \frac{1}{e})$ (d) $S \leq \frac{1}{2} + \frac{1}{e} (1 - \frac{1}{2})$