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Let {p}={()}_{{{x}{{0}}+}}{({1}+{{}^{{2}}{{{x}}}})}^{{{1}/{2}{

Question

Let $p = (lim)_{x 0 +} (1 + tan^{2} x)^{1 / 2 x}$ then $lo g p$ is equal to:

\frac{1}{2}

\frac{1}{4}

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Mila Discussed

Let

p = (lim)_{x 0 +} (1 + tan^{2} x)^{1 / 2 x}

then

lo g p

is equal to:

10 mins ago

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Question Text	Let $p = (lim)_{x 0 +} (1 + tan^{2} x)^{1 / 2 x}$ then $lo g p$ is equal to:
Answer Type	Video solution: 1
Upvotes	150