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Let P be the set of points inside the square, Q be the set of

Question

Let $P$ be the set of points inside the square, $Q$ be the set of points inside the triangle and $R$ be the set of points inside the circle. If the triangle and circle intersect each other and are contained in the square then,

P \cap Q \cap R \neq = ϕ

P \cup Q \cup R = R

P \cup Q \cup R = P

P \cup Q = R \cup P

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Sebastian Discussed

Let

P

be the set of points inside the square,

Q

be the set of points inside the triangle and

R

be the set of points inside the circle. If the triangle and circle intersect each other and are contained in the square then,

11 mins ago

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11 mins ago

Text solutionVerified

P =

The set of points inside the square

Q =

The set of points inside the triangle

R =

The set of points inside the circle

Then

P \cap Q \cap R \neq = ϕ

[Since the set

Q

and

R

intersect each others and are contained in the square.]

And

P \cup Q \cup R = P

[Since the union of

P

and

Q

and

R

is the set of all points inside the square.]

P \cup Q = R \cup P

P = P

[Since the set of points in the triangle and the circle are contained in the square.]

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Question Text	Let $P$ be the set of points inside the square, $Q$ be the set of points inside the triangle and $R$ be the set of points inside the circle. If the triangle and circle intersect each other and are contained in the square then,
Answer Type	Text solution:1
Upvotes	150

Let P be the set of points inside the square, Q be the set of points inside the triangle and R be the set of points inside the circle. If the triangle and circle intersect each other and are contained in the square then,

Text solutionVerified

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Let $P$ be the set of points inside the square, $Q$ be the set of points inside the triangle and $R$ be the set of points inside the circle. If the triangle and circle intersect each other and are contained in the square then,