Let P and Q be 3×3 matrices with P=Q . If P3=Q3andP2Q=Q2P, then determinant of (P2+Q2) is equal to

Name: Video solution 1: Let P and Q be 3×3 matrices with P=Q . If P3=Q3andP2Q=Q2P, then determinant of (P2+Q2) is equal to
Uploaded: 2021-01-01T18:41:02.000Z
Duration: 2 min
Description: Video solution 1: Let P and Q be 3×3 matrices with P=Q . If P3=Q3andP2Q=Q2P, then determinant of (P2+Q2) is equal to

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Let P and Q be {3}{3} matrices with {P}{Q} . If {P}^{{3}}={}{Q

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Let P and Q be $3 \times 3$ matrices with $P \neq = Q$ . If $P^{3} = Q^{3} a n d P^{2} Q = Q^{2} P$ , then determinant of $(P^{2} + Q^{2})$ is equal to

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Daniel Discussed

Let P and Q be

3 \times 3

matrices with

P \neq = Q

. If

P^{3} = Q^{3} a n d P^{2} Q = Q^{2} P

, then determinant of

(P^{2} + Q^{2})

is equal to

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Question Text	Let P and Q be $3 \times 3$ matrices with $P \neq = Q$ . If $P^{3} = Q^{3} a n d P^{2} Q = Q^{2} P$ , then determinant of $(P^{2} + Q^{2})$ is equal to
Answer Type	Video solution: 1
Upvotes	150

Let P and Q be 3×3 matrices with P=Q . If P3=Q3andP2Q=Q2P, then determinant of (P2+Q2) is equal to

Filo tutor solutions (1)

Practice questions from similar books

Let P and Q be $3 \times 3$ matrices with $P \neq = Q$ . If $P^{3} = Q^{3} a n d P^{2} Q = Q^{2} P$ , then determinant of $(P^{2} + Q^{2})$ is equal to