Let $k$be an integer such that the triangle with vertices $\left(k,-3k\right),\left(5,k\right)$and $\left(-k,2\right)$has area $28sq\dot{}$units. Then the orthocentre of this triangle is at the point : $\left(1,-\frac{3}{4}\right)$ (2) $\left(2,\frac{1}{2}\right)$ (3) $\left(2,-\frac{1}{2}\right)$ (4) $\left(1,\frac{3}{4}\right)$

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