Let $g (x) = [3 x^{2} - 4 x + 1 a x + b x < 1 x \geq 1)$ If $g (x)$ is continuous and differentiable for all numbers in its domain then (A) a=b=-4 (B) a=b=4 (C) a=4 and b =-4 (D) a=-4 and b=4

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Let

g (x) = [3 x^{2} - 4 x + 1 a x + b x < 1 x \geq 1)

g (x)

is continuous and differentiable for all numbers in its domain then (A) a=b=-4 (B) a=b=4 (C) a=4 and b =-4 (D) a=-4 and b=4

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Let

g (x) = [3 x^{2} - 4 x + 1 a x + b x < 1 x \geq 1)

g (x)

is continuous and differentiable for all numbers in its domain then (A) a=b=-4 (B) a=b=4 (C) a=4 and b =-4 (D) a=-4 and b=4

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