Let f(x)=(lim)x∞(π3tan−12x)2n+51˙ Then the set of values of x for which f(x)=0 is ∣2x∣>3 (b) ∣2x∣<3 ∣2x∣≥3 (d) ∣2x∣≤3

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Question

Let $f (x) = (lim)_{x \infty} \frac{1}{( \frac{3}{π} tan ^{- 1} 2 x ) ^{2 n} + 5} ˙$ Then the set of values of $x$ for which $f (x) = 0$ is $∣ 2 x ∣ > 3$ (b) $∣ 2 x ∣ < 3$ $∣ 2 x ∣ \geq 3$ (d) $∣ 2 x ∣ \leq 3$

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Noah Discussed

Let

f (x) = (lim)_{x \infty} \frac{1}{( \frac{3}{π} tan ^{- 1} 2 x ) ^{2 n} + 5} ˙

Then the set of values of

x

for which

f (x) = 0

∣ 2 x ∣ > 3

(b)

∣ 2 x ∣ < 3

∣ 2 x ∣ \geq 3

(d)

∣ 2 x ∣ \leq 3

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Question Text

Let

f (x) = (lim)_{x \infty} \frac{1}{( \frac{3}{π} tan ^{- 1} 2 x ) ^{2 n} + 5} ˙

Then the set of values of

x

for which

f (x) = 0

∣ 2 x ∣ > 3

(b)

∣ 2 x ∣ < 3

∣ 2 x ∣ \geq 3

(d)

∣ 2 x ∣ \leq 3