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Let {f{{({x})}}}={_{{1}}^{{x}}}{{{2}-{t}^{{2}}}}{.{d}{t}.}{} T

Question

Let $f (x) = \int_{1}^{x} 2 - t^{2} d t ˙$ Then the real roots of the equation $x^{2} - f^{p r i m e} (x) = 0$ are (a) $\pm 1$ (b) $\pm \frac{1}{2}$ (c) $\pm \frac{1}{2}$ (d) 0 and 1

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Let

f (x) = \int_{1}^{x} 2 - t^{2} d t ˙

Then the real roots of the equation

x^{2} - f^{p r i m e} (x) = 0

are (a)

\pm 1

(b)

\pm \frac{1}{2}

(c)

\pm \frac{1}{2}

(d) 0 and 1

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Question Text

Let

f (x) = \int_{1}^{x} 2 - t^{2} d t ˙

Then the real roots of the equation

x^{2} - f^{p r i m e} (x) = 0

are (a)

\pm 1

(b)

\pm \frac{1}{2}

(c)

\pm \frac{1}{2}

(d) 0 and 1

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