Let A≡{1,2,3,4}, B≡{a,b,c}, then number of function from A→B, which are not onto is

A≡{1,2,3,4}B≡{a,b,c}Total function (A→B) Total onto function (A→B)=4c3×3!×3=3!1!4!×3!×3=41×3=72Hence, no. of fn which are not onto=81−72=9

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Let A {1,2,3,4}, B {a,b,c}, then number of function from A B,

Question

Let $A \equiv {1, 2, 3, 4}, B \equiv {a, b, c}$ , then number of function from $A \to B$ , which are not onto is

9

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Lucas Discussed

Let

A \equiv {1, 2, 3, 4}, B \equiv {a, b, c}

, then number of function from

A \to B

, which are not onto is

6 mins ago

Discuss this question LIVE

6 mins ago

A \equiv {1, 2, 3, 4}

B \equiv {a, b, c}

Total function

(A \to B)

Total onto function (A \to B)

= 4 c_{3} \times 3! \times 3

= \frac{4 !}{3 ! 1 !} \times 3! \times 3

= 41 \times 3 = 72

Hence, no. of

f^{n}

which are not onto

= 81 - 72

= 9

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Question Text	Let $A \equiv {1, 2, 3, 4}, B \equiv {a, b, c}$ , then number of function from $A \to B$ , which are not onto is
Answer Type	Text solution:1
Upvotes	150