Class 12

Math

Algebra

Probability I

Let A, B, C be three events such that P(A) = 0.3, P(B) = 0.4, P(C ) = 0.8, $P(A∩B)$ = 0.08, $P(A∩C)$ = 0.28, $P(A∩B∩C)=0.09$. If $P(A∪B∪C)≥0.75$, then show that $0.23≤P(B∩C)≤0.48$.

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