Let a and b be the roots of equation px2+qx+r=0,p=0.. If p, q, r are in A.P. and α1+β1=4, then the value of ∣α−β∣ is

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Let a and b be the roots of equation {p}{x}^{{2}}+{q}{x}+{r}={

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Let a and b be the roots of equation $p x^{2} + q x + r = 0, p \neq = 0 .$ . If p, q, r are in A.P. and $\frac{1}{α} + \frac{1}{β} = 4$ , then the value of $∣ α - β ∣$ is

\frac{61}{9}

\frac{2 17}{9}

\frac{34}{9}

\frac{2 13}{9}

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Luna Discussed

Let a and b be the roots of equation

p x^{2} + q x + r = 0, p \neq = 0 .

. If p, q, r are in A.P. and

\frac{1}{α} + \frac{1}{β} = 4

, then the value of

∣ α - β ∣

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Question Text	Let a and b be the roots of equation $p x^{2} + q x + r = 0, p \neq = 0 .$ . If p, q, r are in A.P. and $\frac{1}{α} + \frac{1}{β} = 4$ , then the value of $∣ α - β ∣$ is
Answer Type	Video solution: 1
Upvotes	150