Let a1,a2,a3,...,a49 be in A.P. such that k=0∑12a4k+1=416 and a9+a43=66. If a21+a22+...+a172=140m, then m is equal to :

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Let {a_1},{a_2},{a_3},...,{a_{49}} be in A.P. such that _{k =

Question

Let $a_{1}, a_{2}, a_{3}, ..., a_{49}$ be in A.P. such that $k = 0 \sum 12 a_{4 k + 1} = 416$ and $a_{9} + a_{43} = 66$ . If $a_{2}^{1} + a_{2}^{2} + ... + a_{17}^{2} = 140 m$ , then m is equal to :

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Let

a_{1}, a_{2}, a_{3}, ..., a_{49}

be in A.P. such that

k = 0 \sum 12 a_{4 k + 1} = 416

and

a_{9} + a_{43} = 66

. If

a_{2}^{1} + a_{2}^{2} + ... + a_{17}^{2} = 140 m

, then m is equal to :

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Question Text

Let

a_{1}, a_{2}, a_{3}, ..., a_{49}

be in A.P. such that

k = 0 \sum 12 a_{4 k + 1} = 416

and

a_{9} + a_{43} = 66

. If

a_{2}^{1} + a_{2}^{2} + ... + a_{17}^{2} = 140 m

, then m is equal to :