Let 2∣z1∣=3∣z2∣ and 32z2z1+23z1z2=z then (a) real part of z is 0 (b) imaginary part at z is 0 (c) ∣z∣=25 (d) ∣z∣=2217

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Let {2}{|{z}_{{1}}|}={3}{|{z}_{{2}}|} and {{2}}{{3}}{{z}_{{1}}

Question

Let $2 ∣ z_{1} ∣ = 3 ∣ z_{2} ∣$ and $\frac{2}{3} \frac{z _{1}}{z _{2}} + \frac{3}{2} \frac{z _{2}}{z _{1}} = z$ then (a) real part of z is 0 (b) imaginary part at z is 0 (c) $∣ z ∣ = \frac{5}{2}$ (d) $∣ z ∣ = \frac{17}{2 2}$

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Oliver Discussed

Let

2 ∣ z_{1} ∣ = 3 ∣ z_{2} ∣

and

\frac{2}{3} \frac{z _{1}}{z _{2}} + \frac{3}{2} \frac{z _{2}}{z _{1}} = z

then (a) real part of z is 0 (b) imaginary part at z is 0 (c)

∣ z ∣ = \frac{5}{2}

(d)

∣ z ∣ = \frac{17}{2 2}

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Question Text

Let

2 ∣ z_{1} ∣ = 3 ∣ z_{2} ∣

and

\frac{2}{3} \frac{z _{1}}{z _{2}} + \frac{3}{2} \frac{z _{2}}{z _{1}} = z

then (a) real part of z is 0 (b) imaginary part at z is 0 (c)

∣ z ∣ = \frac{5}{2}

(d)

∣ z ∣ = \frac{17}{2 2}