In the expansion of (x2−x1)2 find(i) 4 th term(ii) middle term(iii) term independent of x

(x2−x1)2=x4+(x1)2−2x2x1=x4+(x1)2−2x(i) 4 th term=0(ii) middle term=(x1)2(iii) term independent of x =0

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In the expansion of {({x}^{2}-{1}{x})}^{2} find (i) 4 th term

Question

In the expansion of $(x^{2} - \frac{1}{x})^{2}$ find
(i) 4 th term
(ii) middle term
(iii) term independent of $x$

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Camila Discussed

In the expansion of

(x^{2} - \frac{1}{x})^{2}

find
(i) 4 th term
(ii) middle term
(iii) term independent of

x

13 mins ago

Discuss this question LIVE

13 mins ago

(x^{2} - \frac{1}{x})^{2}

= x^{4} + (\frac{1}{x})^{2} - 2 x^{2} \frac{1}{x}

= x^{4} + (\frac{1}{x})^{2} - 2 x

(i) 4 th term

= 0

(ii) middle term

= (\frac{1}{x})^{2}

(iii) term independent of

= 0

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Question Text	In the expansion of $(x^{2} - \frac{1}{x})^{2}$ find (i) 4 th term (ii) middle term (iii) term independent of $x$
Answer Type	Text solution:1
Upvotes	150