In the expansion of (3x−x21 ) 10, the 5th term from the end is

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In the expansion of { ( 3x- { 1 }{ { x }^{ 2 } } ) }^{ 10 },

Question

In the expansion of $(3 x - \frac{1}{x ^{2}})^{10}$ , the $5^{t h}$ term from the end is

\frac{16486}{x ^{8}}

\frac{17010}{x ^{8}}

\frac{13486}{x ^{8}}

None of these

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Owen Discussed

In the expansion of

(3 x - \frac{1}{x ^{2}})^{10}

, the

5^{t h}

term from the end is

9 mins ago

Discuss this question LIVE

9 mins ago

There are

11

terms in the expansion of

(3 x - \frac{1}{x ^{2}})^{10}

Therefore,

5^{t h}

term from the end.

= (10 - 5 + 2)^{t h}

term from beginning

= T_{7} =_{10} C_{6} (3 x)^{10 - 6} (- \frac{1}{x ^{2}})^{6}

= \frac{10 !}{6 ! 4 !} 3^{4} x^{4} \frac{1}{x ^{12}}

= \frac{17010}{x ^{8}}

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Question Text	In the expansion of $(3 x - \frac{1}{x ^{2}})^{10}$ , the $5^{t h}$ term from the end is
Answer Type	Text solution:1
Upvotes	150