In the binomial expansion of (a−b)n,n≥5,the sum of 5th and 6th terms is zero, then baequals
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If a and b
are distinct integers, prove that an−bn
is divisible by (a−b)
Find the 11th term form the beginning and the 11th term form the end I the expansion of (2x−x21)25˙
Find the 6th term in the expansion of (54x−2x5)9.
Consider a G.P. with first term (1+x)n, ∣x∣<1, common ratio 21+x and number of terms (n+1). Let ′S′ be sum of all the terms of the G.P., then r=0∑nn+rCr(21)r equals
Expand using Binomial Theorem (1+2x−x2)4,x=0 and let the sum of coefficients of the terms in the expansion be t. Find 10000t
Evaluate the following: (3+1)5−(3−1)5
Which of the following is/are correct ?
The value of k=0∑7⎣⎡(14k)(7k)r=k∑14(rk)(14r)⎦⎤, where (nr) denotes nCr is