In a high school, a committee has to be formed from a group of 6 boys $M_1,M_2,M_3,M_4,M_5,M_6$and 5 girls $G_1,G_2,G_3,G_4,G_5$.Let ${\alpha }_1$be the total number of ways in which the committee can be formed such that the committee has 5 members, having exactly 3 boys and 2 girls.(ii) Let ${\alpha }_2$be the total number of ways in which the committee can be formed such that the committee has at least 2 members, and having an equal number of boys and girls.(iii) Let ${\alpha }_3$be the total number of ways in which the committee can be formed such that the committee has 5 members, at least 2 of them being girls.(iv) Let ${\alpha }_4$be the total number of ways in which the committee can be formed such that the committee has 4 members, having at least 2 girls and such that both $M_1$and $G_1$are NOT in the committee together.LIST-I LIST-IIP. The value of ${\alpha }_1$is 1. $136$Q. The value of ${\alpha }_2$is 2. $189$R. The value of ${\alpha }_3$is 3. $192$S. The value of ${\alpha }_4$is 4. $200$5. $381$6. $461$The correct option is:$P\to 4;Q\to 6;R\to 2;S\to 1$(b) $P\to 1;Q\to 4;R\to 2;S\to 3$(c) $P\to 4;Q\to 6;R\to 5;S\to 2$(d) $P\to 4;Q\to 2;R\to 3;S\to 1$

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