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In a conference 10 speakers are present . if  wants to speak before  wants to speak after  then the number of ways all the 10 speakers can give their speeches with the above restriction if the remaining seven speakers have no objection to speak at any number is 

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Text SolutionText solutionverified iconVerified

This is a question on permutation and combination. 
There are speakers where the restrictions do not apply. 
For the first three speakers we have
  can also speak before
There are two possibilities for and to take place and there is no third possibility. 
For it has to remain in the same position.
We have,
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Question Text
In a conference 10 speakers are present . if  wants to speak before  wants to speak after  then the number of ways all the 10 speakers can give their speeches with the above restriction if the remaining seven speakers have no objection to speak at any number is 
Answer TypeText solution:1
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