If y(x) satisfies the differential equation yprime−ytanx=2xsecx and y(0)=0 , then
The general solution of the differential equation dxdy=ex+yis(A) ex+e−y=C (B) ex+ey=C(C) e−x+ey=C (D) e−x+e−y=C
At any point (x, y) of a curve, the slope of the tangent is twice the slope of the line segment joining the point of contact to the point (4,3). Find the equation of the curve given that it passes through (2,1).
Find a particular solution of the differential equation(x−y)(dx+dy)=dxdy, given that y=1, when x=0. (Hint: put x−y=t).
Verify that the given functions (explicit or implicit) is a solution of the corresponding differential equation: y=xsinx : xyprime=y+xx2−y2(x=0andx>yorx<y)
The differential equations, find a particular solution satisfying the given condition: x(x2−1)dxdy=1;y=0when x=2