If y=cot−1[1+sinx−1−sinx1+sinx+1−sinx](0<x<π/2), then dxdy=

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$If y = cot^{- 1} [\frac{1 + sin x + 1 - sin x}{1 + sin x - 1 - sin x}] (0 < x < π / 2), then \frac{d y}{d x} =$

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If y = cot^{- 1} [\frac{1 + sin x + 1 - sin x}{1 + sin x - 1 - sin x}] (0 < x < π / 2), then \frac{d y}{d x} =

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Question Text

If y = cot^{- 1} [\frac{1 + sin x + 1 - sin x}{1 + sin x - 1 - sin x}] (0 < x < π / 2), then \frac{d y}{d x} =