If y2=4b(x−c) and y2=8ax having common normal then (a,b,c) is (A) (21,2,0) (B) (1,1,3) (C) (1,1,1) (D) (1,3,2)

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If {y}^{{2}}={4}{b}{({x}-{c})} and {y}^{{2}}={8}{a}{x} having

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If $y^{2} = 4 b (x - c)$ and $y^{2} = 8 a x$ having common normal then $(a, b, c)$ is (A) $(\frac{1}{2}, 2, 0)$ (B) $(1, 1, 3)$ (C) $(1, 1, 1)$ (D) $(1, 3, 2)$

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Emily Discussed

y^{2} = 4 b (x - c)

and

y^{2} = 8 a x

having common normal then

(a, b, c)

is (A)

(\frac{1}{2}, 2, 0)

(B)

(1, 1, 3)

(C)

(1, 1, 1)

(D)

(1, 3, 2)

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Question Text	If $y^{2} = 4 b (x - c)$ and $y^{2} = 8 a x$ having common normal then $(a, b, c)$ is (A) $(\frac{1}{2}, 2, 0)$ (B) $(1, 1, 3)$ (C) $(1, 1, 1)$ (D) $(1, 3, 2)$
Answer Type	Video solution: 1
Upvotes	150