If x satisfies the condition f(x)={x:x2+30≤11x} then maximum value of function f(x)=3x3−18x2−27x−40 is equal to (A) −122 (B) 122 (C) 222 (D) −222

Click here to view the solution.

Get 2 FREE Instant-Explanations on Filo with code FILOAPP

If {x} satisfies the condition {f{{({x})}}}={{x}:{x}^{{2}}+{3}

Question

If $x$ satisfies the condition $f (x) = {x : x^{2} + 30 \leq 11 x}$ then maximum value of function $f (x) = 3 x^{3} - 18 x^{2} - 27 x - 40$ is equal to (A) $- 122$ (B) $122$ (C) $222$ (D) $- 222$

Views: 769 students

Found 4 tutors discussing this question

Henry Discussed

x

satisfies the condition

f (x) = {x : x^{2} + 30 \leq 11 x}

then maximum value of function

f (x) = 3 x^{3} - 18 x^{2} - 27 x - 40

is equal to (A)

- 122

(B)

122

(C)

222

(D)

- 222

12 mins ago

Discuss this question LIVE

12 mins ago

One destination to cover all your homework and assignment needs

Learn Practice Revision Succeed

Instant 1:1 help, 24x7

60, 000+ Expert tutors

Textbook solutions

Big idea maths, McGraw-Hill Education etc

Essay review

Get expert feedback on your essay

Schedule classes

High dosage tutoring from Dedicated 3 experts

Trusted by 4 million+ students

Stuck on the question or explanation?

Connect with our maths tutors online and get step by step solution of this question.

231 students are taking LIVE classes

Question Text

x

satisfies the condition

f (x) = {x : x^{2} + 30 \leq 11 x}

then maximum value of function

f (x) = 3 x^{3} - 18 x^{2} - 27 x - 40

is equal to (A)

- 122

(B)

122

(C)

222

(D)

- 222