If i=1∑9(xi−5) andi=1∑9(xi−5)2=45, then the standard deviation of the 9 items x1,x2,..,x9 is

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If $i = 1 \sum 9 (x_{i} - 5) and i = 1 \sum 9 (x_{i} - 5)^{2} = 45$ , then the standard deviation of the 9 items $x_{1}, x_{2}, .., x_{9}$ is

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Elijah Discussed

i = 1 \sum 9 (x_{i} - 5) and i = 1 \sum 9 (x_{i} - 5)^{2} = 45

, then the standard deviation of the 9 items

x_{1}, x_{2}, .., x_{9}

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Question Text

i = 1 \sum 9 (x_{i} - 5) and i = 1 \sum 9 (x_{i} - 5)^{2} = 45

, then the standard deviation of the 9 items

x_{1}, x_{2}, .., x_{9}