If U = {2, 3, 4, 6}, A = {5, 0}, B = {1, 2, 4, 3} then prove $(A∩B)_{_{′}} =A_{_{′}}∪B_{_{′}}$

**Solution: **$A⋂B=ϕA⋃B={0,1,2,3,4,5}$

$(A⋂B )_{_{′}}={2,3,4,6}$

$A_{_{′}}={2,3,4,6},B_{_{′}}={6}$

$A_{_{′}}⋃B_{_{′}}={2,3,4,6}$

$⇒(A⋂B )_{_{′}}=A_{_{′}}⋃B_{_{′}}$ (proved)