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If the points (k, 2-2k), (1-k, 2k) and (-k-4, 6-2k) be colline

Question

If the points $(k, 2 - 2 k)$ , $(1 - k, 2 k)$ and $(- k - 4, 6 - 2 k)$ be collinear, the number of possible values of $k$ are

4

2

1

3

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If the points

(k, 2 - 2 k)

(1 - k, 2 k)

and

(- k - 4, 6 - 2 k)

be collinear, the number of possible values of

k

are

14 mins ago

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Text solutionVerified

(k, 2 - 2 k), (1 - k, 2 k)

(- k - 4, 6 - 2 k)

if collinear the

m_{1} = m_{2}

\frac{2 k - 2 + 2 k}{1 - k - k} = \frac{6 - 2 k - 2 k}{- k - 4 - 1 + k}

\frac{4 k - 2}{1 - 2 k} = \frac{6 - 4 k}{- 5}

\frac{2 k - 1}{1 - 2 k} = \frac{3 - 2 k}{- 5}

5 = 3 - 2 k

2 k = - 2

k = - 1

Only

1

value possible.

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Question Text	If the points $(k, 2 - 2 k)$ , $(1 - k, 2 k)$ and $(- k - 4, 6 - 2 k)$ be collinear, the number of possible values of $k$ are
Answer Type	Text solution:1
Upvotes	150