If the lines 1x−2=1y−3=−kx−4 and kx−1=2y−4=1x−5are coplanar, then k can have

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If the lines {{{x}-{2}}}{{1}}={{{y}-{3}}}{{1}}={{{x}-{4}}}{{-{

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If the lines $\frac{x - 2}{1} = \frac{y - 3}{1} = \frac{x - 4}{- k}$ and $\frac{x - 1}{k} = \frac{y - 4}{2} = \frac{x - 5}{1}$ are coplanar, then k can have

exactly one value

exactly two values

exactly three values

any value

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Lucas Discussed

If the lines

\frac{x - 2}{1} = \frac{y - 3}{1} = \frac{x - 4}{- k}

and

\frac{x - 1}{k} = \frac{y - 4}{2} = \frac{x - 5}{1}

are coplanar, then k can have

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Question Text	If the lines $\frac{x - 2}{1} = \frac{y - 3}{1} = \frac{x - 4}{- k}$ and $\frac{x - 1}{k} = \frac{y - 4}{2} = \frac{x - 5}{1}$ are coplanar, then k can have
Answer Type	Video solution: 1
Upvotes	150