If the eccentric angles of two points P and Q on the ellipse 28x2+7y2=1 whose center is C, differ by a right angle, then the area of ΔCPQ is

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If the eccentric angles of two points P and Q on the ellipse {

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If the eccentric angles of two points P and Q on the ellipse $\frac{x ^{2}}{28} + \frac{y ^{2}}{7} = 1$ whose center is C, differ by a right angle, then the area of $Δ C P Q$ is

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Michael Discussed

If the eccentric angles of two points P and Q on the ellipse

\frac{x ^{2}}{28} + \frac{y ^{2}}{7} = 1

whose center is C, differ by a right angle, then the area of

Δ C P Q

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Question Text

If the eccentric angles of two points P and Q on the ellipse

\frac{x ^{2}}{28} + \frac{y ^{2}}{7} = 1

whose center is C, differ by a right angle, then the area of

Δ C P Q