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If the curves {y}^{{2}}={6}{x}, {9}{x}^{{2}}+{b}{y}^{{2}}={16}

Question

If the curves $y^{2} = 6 x$ , $9 x^{2} + b y^{2} = 16$ intersect each other at right angles then the value of b is:

\frac{7}{2}

4

\frac{9}{2}

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Asher Discussed

If the curves

y^{2} = 6 x

9 x^{2} + b y^{2} = 16

intersect each other at right angles then the value of b is:

7 mins ago

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7 mins ago

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Question Text	If the curves $y^{2} = 6 x$ , $9 x^{2} + b y^{2} = 16$ intersect each other at right angles then the value of b is:
Answer Type	Video solution: 1
Upvotes	150