Get 2 FREE Instant-Explanations on Filo with code FILOAPP

If tan^{-1}y=4tan^{-1}x,(|x|<tan{}{8}), find y as an algebraic

Question

If $t a n^{- 1} y = 4 t a n^{- 1} x (∣ x ∣ < t an \frac{π}{8})$ , find y as an algebraic function of x, and hence, prove that $tan π /8$ is a root of the equation $x^{4} - 6 x + 1 = 0$ $$

Views: 713 students

Found 5 tutors discussing this question

Sophia Discussed

t a n^{- 1} y = 4 t a n^{- 1} x (∣ x ∣ < t an \frac{π}{8})

, find y as an algebraic function of x, and hence, prove that

tan π /8

is a root of the equation

x^{4} - 6 x + 1 = 0

12 mins ago

Discuss this question LIVE

12 mins ago

Text solutionVerified

We have

t a n^{- 1} y = 4 t a n^{- 1} x

\Rightarrow tan^{- 1} y = 2 tan^{- 1} \frac{2 x}{1 - x ^{2}} (a s ∣ x ∣ < 1)

= tan^{- 1} \frac{\frac{4 x}{1 - x ^{2}}}{1 - \frac{4 x ^{2}}{( 1 - x ^{2} ) ^{2}}}

= tan^{- 1} \frac{4 x ( 1 - x ^{2} )}{x ^{4} - 6 x ^{2} + 1}

\Rightarrow y = \frac{4 x ( 1 - x ^{2} )}{x ^{4} - 6 x ^{2} + 1}

x = \frac{π}{8} \Rightarrow t a n^{- 1} y = 4 tan^{- 1} x = \frac{π}{2} \Rightarrow y \to \infty \Rightarrow x^{4} - 6 x^{2} + 1 = 0

Hence,

tan \frac{π}{8}

is a root of

x^{4} - 6 x^{2} + 1 = 0

Was this solution helpful?

150

Report

One destination to cover all your homework and assignment needs

Learn Practice Revision Succeed

Instant 1:1 help, 24x7

60, 000+ Expert tutors

Textbook solutions

Big idea maths, McGraw-Hill Education etc

Essay review

Get expert feedback on your essay

Schedule classes

High dosage tutoring from Dedicated 3 experts

Trusted by 4 million+ students

Stuck on the question or explanation?

Connect with our maths tutors online and get step by step solution of this question.

231 students are taking LIVE classes

Question Text	If $t a n^{- 1} y = 4 t a n^{- 1} x (∣ x ∣ < t an \frac{π}{8})$ , find y as an algebraic function of x, and hence, prove that $tan π /8$ is a root of the equation $x^{4} - 6 x + 1 = 0$ $$
Answer Type	Text solution:1
Upvotes	150