If tan−1(x+2)+tan−1(x−2)=tan−1(21), then sum of value(s) of x is equal to

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If ^{-1}(x+2)+^{-1}(x-2)=^{-1}({1}{2}), then sum of value(s) o

Question

If $tan^{- 1} (x + 2) + tan^{- 1} (x - 2) = tan^{- 1} (\frac{1}{2})$ , then sum of value(s) of $x$ is equal to

1

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\frac{1}{2}

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Samuel Discussed

tan^{- 1} (x + 2) + tan^{- 1} (x - 2) = tan^{- 1} (\frac{1}{2})

, then sum of value(s) of

x

is equal to

15 mins ago

Discuss this question LIVE

15 mins ago

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Question Text

tan^{- 1} (x + 2) + tan^{- 1} (x - 2) = tan^{- 1} (\frac{1}{2})

, then sum of value(s) of

x

is equal to